\u0110\u00e3 l\u00e0 d\u00e2n ch\u01a1i b\u1ed9 m\u00f4n s\u1ed1 h\u1ecdc th\u00ec t\u00ednh ti\u1ec1n l\u1eddi l\u00e0 \u0111i\u1ec1u t\u1ea5t y\u1ebfu \u0111\u1ea7u ti\u00ean.Tuy nhi\u00ean, \u0111\u00e3 l\u00e0 m\u1ed9t l\u00f4 th\u1ee7 th\u00ec l\u1eddi gi\u1ea3i \u0111\u00e1p c\u1ee7a c\u00e2u h\u1ecfi 1 \u0111i\u1ec3m l\u00f4 \u0103n bao nhi\u00eau \u0111\u00e3 qu\u00e1 r\u00f5 r\u00e0ng. Mu\u1ed1n t\u00ednh \u0111\u01b0\u1ee3c \u0111i\u1ec3m l\u00f4 c\u1ee5 th\u1ec3 c\u1ea7n d\u1ef1a v\u00e0o l\u00f4 \u0111\u1ec1 t\u1eebng mi\u1ec1n c\u0169ng nh\u01b0 lo\u1ea1i l\u00f4 kh\u00e1c nhau c\u0169ng nh\u01b0 nh\u1eefng h\u00ecnh th\u1ee9c \u0111\u00e1nh ch\u01a1i ngo\u00e0i hay ch\u01a1i online. B\u00e0i vi\u1ebft n\u00e0y, ch\u00fang t\u00f4i s\u1ebd cung c\u1ea5p \u0111\u1ea7y \u0111\u1ee7 v\u1ec1 c\u00e1ch t\u00ednh \u0111i\u1ec3m, ti\u1ec1n \u0103n khi tr\u00fang l\u00f4 \u0111\u1ed1i v\u1edbi 3 mi\u1ec1n c\u0169ng nh\u01b0 cung c\u1ea5p \u0111\u1ecba ch\u1ec9 c\u00f3 t\u1ef7 l\u1ec7 \u0103n cao nh\u1ea5t th\u1ecb tr\u01b0\u1eddng hi\u1ec7n nay.<\/em><\/p>\n Tr\u01b0\u1edbc khi tr\u1ea3 l\u1eddi c\u00e2u h\u1ecfi m\u1ed9t \u0111i\u1ec3m l\u00f4 bao nhi\u00eau ti\u1ec1n th\u00ec anh em c\u1ea7n n\u1eafm r\u00f5 th\u1ebf n\u00e0o l\u00e0 l\u00f4 v\u00e0 tr\u01b0\u1eddng h\u1ee3p n\u00e0o \u0111\u01b0\u1ee3c t\u00ednh l\u00e0 tr\u00fang l\u00f4. C\u00f3 th\u1ec3 hi\u1ec3u \u0111\u01a1n gi\u1ea3n th\u00ec l\u00f4 ch\u00ednh l\u00e0 2 con s\u1ed1 cu\u1ed1i c\u1ee7a c\u00e1c gi\u1ea3i trong b\u1ea3ng KQXS. Ch\u01a1i l\u00f4 c\u0169ng ch\u00ednh l\u00e0 vi\u1ec7c ng\u01b0\u1eddi ch\u01a1i ch\u1ecdn v\u00e0 \u0111\u00e1nh 2 con s\u1ed1 trong d\u00e3y t\u1eeb 00 \u2013 99.<\/p>\n Tr\u01b0\u1eddng h\u1ee3p 2 s\u1ed1 cu\u1ed1i c\u1ee7a c\u00e1c gi\u1ea3i v\u1ec1 tr\u00f9ng th\u1ee9 t\u1ef1 v\u1edbi 2 con s\u1ed1 m\u00e0 anh em \u0111\u00e3 ch\u1ecdn th\u00ec \u0111\u01b0\u1ee3c t\u00ednh l\u00e0 tr\u00fang l\u00f4. Ngo\u00e0i c\u00e1ch \u0111\u00e1nh l\u00f4 c\u01a1 b\u1ea3n tr\u00ean c\u00f2n c\u00f3 nhi\u1ec1u lo\u1ea1i l\u00f4 kh\u00e1c \u0111\u1ec3 anh em l\u1ef1a ch\u1ecdn. \u0110i\u1ec3n h\u00ecnh l\u00e0 l\u00f4 xi\u00ean, l\u00f4 k\u00e9p, l\u00f4 tr\u01b0\u1ee3t. 1 \u0111i\u1ec3m l\u00f4 l\u00e0 bao nhi\u00eau ti\u1ec1n? V\u1ec1 s\u1ed1 ti\u1ec1n thu \u0111\u01b0\u1ee3c sau khi tr\u00fang m\u1ed9t \u0111i\u1ec3m l\u00f4 s\u1ebd t\u00f9y thu\u1ed9c v\u00e0o t\u1eebng lo\u1ea1i l\u00f4 m\u00e0 anh em ch\u01a1i. \u0110\u1ec3 c\u00f3 th\u1ec3 t\u1ed1i \u01b0u h\u00f3a l\u1ee3i nhu\u1eadn c\u1ee7a m\u00ecnh th\u00ec ng\u01b0\u1eddi ch\u01a1i n\u00ean ch\u1ecdn ch\u00f4i \u1edf nh\u1eefng \u0111i\u1ec3m c\u00f3 t\u1ef7 l\u1ec7 \u0103n cao nh\u1ea5t v\u00e0 uy t\u00edn.<\/p>\n \u0110\u00e1nh 1 \u0111i\u1ec3m l\u00f4 tr\u00fang bao nhi\u00eau ti\u1ec1n? Nh\u01b0 \u0111\u00e3 chia s\u1ebb, mu\u1ed1n bi\u1ebft s\u1ed1 ti\u1ec1n m\u00ecnh thu v\u1ec1 \u0111\u01b0\u1ee3c khi \u0111\u00e1nh tr\u00fang l\u00f4 th\u00ec anh em c\u1ea7n x\u00e9t t\u1edbi tr\u01b0\u1eddng h\u1ee3p c\u1ee5 th\u1ec3. Khi \u0111\u00e1nh l\u00f4, ch\u1eafc ch\u1eafn anh em s\u1ebd ph\u1ea3i b\u1ecf ra m\u1ed9t s\u1ed1 ti\u1ec1n c\u01b0\u1ee3c. M\u1ed9t \u0111i\u1ec3m s\u1ebd t\u01b0\u01a1ng \u1ee9ng v\u1edbi s\u1ed1 ti\u1ec1n nh\u1ea5t \u0111\u1ecbnh theo t\u1eebng \u0111\u00e0i. T\u01b0\u01a1ng t\u1ef1, s\u1ed1 ti\u1ec1n \u0103n \u0111\u01b0\u1ee3c c\u0169ng ph\u1ee5 thu\u1ed9c v\u00e0o \u0111i\u1ec1u n\u00e0y.<\/p>\n \u0110\u1ed1i v\u1edbi l\u00f4 \u0111\u1ec1 mi\u1ec1n B\u1eafc, 1 \u0111i\u1ec3m l\u00f4 = 23.000\u0111. Ngo\u00e0i ra, s\u1ebd c\u00f3 m\u1ed9t s\u1ed1 n\u01a1i \u0111\u1eb7t ra quy \u0111\u1ecbnh v\u1edbi s\u1ed1 ti\u1ec1n l\u00e0 22.500\u0111\/\u0111i\u1ec3m. 1 \u0111i\u1ec3m l\u00f4 bao nhi\u00eau ti\u1ec1n? N\u1ebfu ch\u01a1i l\u00f4 \u0111\u1ec1 mi\u1ec1n B\u1eafc, tr\u00fang 1 \u0111i\u1ec3m l\u00f4 anh em s\u1ebd \u0103n 80.000\u0111.<\/p>\n V\u1edbi l\u00f4 \u0111\u1ec1 mi\u1ec1n Trung, 1 \u0111i\u1ec3m l\u00f4 = 13.500 \u2013 15.000\u0111. Tr\u00fang 1 \u0111i\u1ec3m l\u00f4 mi\u1ec1n Trung \u0103n 80.000\u0111. Tuy nhi\u00ean \u0111\u00e2y l\u00e0 t\u1ef7 l\u1ec7 \u0103n l\u00f4 th\u00f4ng th\u01b0\u1eddng.<\/p>\n Th\u00f4ng th\u01b0\u1eddng n\u1ebfu ch\u01a1i t\u1ea1i c\u1ea7m b\u1ea3ng b\u00ean ngo\u00e0i, 1 \u0111i\u1ec3m l\u00f4 mi\u1ec1n Trung = 16.000\u0111. Tr\u00fang 1 \u0111i\u1ec3m \u0103n 80.000\u0111.<\/p>\n <\/p>\n L\u00f4 xi\u00ean t\u1ee9c l\u00e0 c\u00e1ch \u0111\u00e1nh 2 ho\u1eb7c nhi\u1ec1u con l\u00f4 trong c\u00f9ng 1 \u0111\u01a1n c\u01b0\u1ee3c. \u0110\u01a1n c\u01b0\u1ee3c coi l\u00e0 th\u1eafng khi t\u1ea5t c\u1ea3 c\u00e1c con l\u00f4 trong \u0111\u01a1n \u0111\u1ec1u v\u1ec1. L\u00f4 xi\u00ean t\u00f9y t\u1eebng n\u01a1i c\u00f3 t\u1ef7 l\u1ec7 \u0103n kh\u00e1c nhau, ng\u01b0\u1eddi ch\u01a1i n\u00ean ch\u1ecdn \u0111\u1ecba ch\u1ec9 uy t\u00edn v\u00e0 c\u00f3 t\u1ef7 l\u1ec7 \u0103n cao \u0111\u1ec3 v\u00e0o ti\u1ec1n.<\/p>\n So v\u1edbi c\u00e1ch ch\u01a1i l\u00f4 truy\u1ec1n th\u1ed1ng th\u00ec l\u00f4 xi\u00ean \u0111\u01b0\u1ee3c r\u1ea5t nhi\u1ec1u anh em l\u00f4 th\u1ee7 l\u1ef1a ch\u1ecdn. L\u00fd do l\u00e0 lo\u1ea1i l\u00f4 n\u00e0y d\u1ec5 ch\u01a1i, d\u1ec5 hi\u1ec3u, t\u1ef7 l\u1ec7 tr\u00fang c\u0169ng kh\u00e1 h\u1ea5p d\u1eabn. C\u00e1ch t\u00ednh ti\u1ec1n c\u1ee7a lo\u1ea1i l\u00f4 n\u00e0y c\u0169ng kh\u00f4ng h\u1ec1 ph\u1ee9c t\u1ea1p. Mu\u1ed1n bi\u1ebft 1 \u0111i\u1ec3m l\u00f4 xi\u00ean \u0103n bao nhi\u00eau th\u00ec anh em h\u00e3y d\u1ef1a v\u00e0o lo\u1ea1i l\u00f4 xi\u00ean m\u00e0 m\u00ecnh \u0111\u00e1nh. C\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n \u0110\u00e1nh 1 \u0111i\u1ec3m l\u00f4 tr\u00fang bao nhi\u00eau ti\u1ec1n? V\u1edbi l\u00f4 xi\u00ean 2, anh em s\u1ebd ch\u1ecdn 2 con l\u00f4 \u0111\u1ec3 \u0111\u00e1nh. N\u1ebfu c\u1ea3 2 con c\u00f9ng v\u1ec1 trong ng\u00e0y th\u00ec anh em \u0111\u00e3 tr\u00fang l\u00f4 xi\u00ean. T\u1ef7 l\u1ec7 \u0103n c\u1ee7a l\u00f4 xi\u00ean th\u00f4ng th\u01b0\u1eddng b\u00ean ngo\u00e0i l\u00e0 2 l\u00e0 1:10. T\u1ee9c l\u00e0 n\u1ebfu anh em ch\u01a1i 1.000\u0111 \u2013 1 c\u1eb7p l\u00f4 xi\u00ean \u0111\u00f4i th\u00ec s\u1ed1 ti\u1ec1n tr\u00fang s\u1ebd l\u00e0 10.000\u0111 (\u0111\u00e0i B\u1eafc). Tuy nhi\u00ean, c\u00e1ch t\u00ednh n\u00e0y kh\u00f4ng \u00e1p d\u1ee5ng m\u1ed9t c\u00e1ch c\u1ed1 \u0111\u1ecbnh c\u0169ng nh\u01b0 cho c\u1ea3 3 mi\u1ec1n. M\u1ed7i nh\u00e0 c\u00e1i s\u1ebd \u00e1p d\u1ee5ng m\u1ed9t c\u00e1ch t\u00ednh ri\u00eang, nh\u00ecn chung th\u01b0\u1eddng dao \u0111\u1ed9ng trong kho\u1ea3ng 1 \u0111i\u1ec3m l\u00f4 xi\u00ean 2 \u0103n 10 \u2013 17 l\u1ea7n.<\/p>\n 1 \u0111i\u1ec3m l\u00f4 3 c\u00e0ng bao nhi\u00eau ti\u1ec1n? L\u00f4 xi\u00ean 3 l\u00e0 h\u00ecnh th\u1ee9c ch\u01a1i c\u00f3 t\u1ef7 l\u1ec7 tr\u00fang th\u1ea5p h\u01a1n so v\u1edbi l\u00f4 xi\u00ean 2. Tuy nhi\u00ean, n\u1ebfu tr\u00fang th\u00ec anh em s\u1ebd thu \u0111\u01b0\u1ee3c s\u1ed1 ti\u1ec1n cao h\u01a1n r\u1ea5t nhi\u1ec1u. C\u1ee5 th\u1ec3, thay v\u00ec ch\u1ecdn ra 2 con s\u1ed1 th\u00ec anh em s\u1ebd t\u00ednh to\u00e1n, l\u1ef1a ch\u1ecdn 3 con s\u1ed1.<\/p>\n L\u00f4 xi\u00ean 3 mi\u1ec1n B\u1eafc c\u00f3 t\u1ef7 l\u1ec7 \u0103n l\u00e0 1:40, tr\u00fang 1 \u0111i\u1ec3m \u0103n 40.000\u0111. V\u1edbi m\u1ed9t s\u1ed1 nh\u00e0 c\u00e1i 1 \u0111i\u1ec3m l\u00f4 xi\u00ean 3 c\u00f3 th\u1ec3 \u0103n v\u1edbi t\u1ef7 l\u1ec7 c\u1ef1c \u201cxanh ch\u00edn\u201d l\u00e0 1:76. \u0110\u1ed1i v\u1edbi l\u00f4 xi\u00ean 3 mi\u1ec1n Trung, Nam th\u00ec t\u1ef7 l\u1ec7 \u0103n l\u00e0 1:80.<\/p>\n L\u00f4 xi\u00ean 2 ch\u1ecdn 2 con s\u1ed1, xi\u00ean 3 ch\u1ecdn 3 con, t\u01b0\u01a1ng t\u1ef1 n\u1ebfu ch\u01a1i l\u00f4 xi\u00ean 4 anh em s\u1ebd t\u00ednh to\u00e1n, ph\u00e2n t\u00edch \u0111\u1ec3 ch\u1ecdn \u0111\u01b0\u1ee3c 4 con s\u1ed1. N\u1ebfu tr\u00fang th\u00ec t\u1ef7 l\u1ec7 \u0103n l\u00e0 1:100, t\u1ee9c l\u00e0 n\u1ebfu tr\u00fang 1 \u0111i\u1ec3m l\u00f4 xi\u00ean 4 anh em s\u1ebd \u0103n s\u1ed1 ti\u1ec1n g\u1ea5p 100 l\u1ea7n ti\u1ec1n c\u01b0\u1ee3c.<\/p>\n C\u00e1ch t\u00ednh \u0111i\u1ec3m l\u00f4 \u0111\u1ec1 v\u1edbi d\u1ea1ng l\u00f4 tr\u01b0\u1ee3t c\u0169ng \u0111\u01b0\u1ee3c \u0111\u00f4ng \u0111\u1ea3o anh em quan t\u00e2m. Thay v\u00ec \u0111\u00e1nh l\u00f4 truy\u1ec1n th\u1ed1ng, nhi\u1ec1u anh em th\u00edch tr\u1ea3i nghi\u1ec7m c\u1ea3m gi\u00e1c m\u1edbi v\u1edbi l\u00f4 tr\u01b0\u1ee3t. Thay v\u00ec d\u1ef1 \u0111o\u00e1n s\u1ed1 v\u1ec1 th\u00f4ng th\u01b0\u1eddng th\u00ec anh em s\u1ebd \u0111\u00e1nh l\u00f4 theo nh\u1eefng con s\u1ed1 kh\u00f4ng v\u1ec1.<\/p>\n Mu\u1ed1n bi\u1ebft \u0111\u00e1nh 1 \u0111i\u1ec3m l\u00f4 tr\u00fang bao nhi\u00eau ti\u1ec1n th\u00ec c\u1ea7n d\u1ef1a v\u00e0o t\u1eebng lo\u1ea1i l\u00f4 c\u1ee5 th\u1ec3. V\u1edbi l\u00f4 tr\u01b0\u1ee3t s\u1ebd c\u00f3 5 h\u00ecnh th\u1ee9c kh\u00e1c nhau. C\u1ee5 th\u1ec3 l\u00e0 l\u00f4 tr\u01b0\u1ee3t 6, 7, 8, 9, 10 con.<\/p>\n Khi \u0111\u00e3 bi\u1ebft \u0111\u00e1nh 1 \u0111i\u1ec3m l\u00f4 tr\u00fang bao nhi\u00eau ti\u1ec1n anh em c\u00f3 th\u1ec3 d\u1ef1a v\u00e0o \u0111\u00f3 \u0111\u1ec3 t\u00ednh s\u1ed1 ti\u1ec1n m\u00ecnh nh\u1eadn \u0111\u01b0\u1ee3c v\u1edbi s\u1ed1 \u0111i\u1ec3m \u0111\u00e1nh c\u1ee5 th\u1ec3. Th\u01b0\u1eddng th\u00ec nh\u1eefng anh em ch\u01a1i l\u00e2u n\u0103m m\u1ed7i l\u1ea7n ch\u01a1i s\u1ebd \u0111\u00e1nh r\u1ea5t nhi\u1ec1u \u0111i\u1ec3m. Kh\u00f4ng ph\u1ea3i 1 m\u00e0 l\u00e0 10, 30, 50, th\u1eadm ch\u00ed l\u00e0 h\u00e0ng tr\u0103m \u0111i\u1ec3m l\u00f4. 10 \u0111i\u1ec3m l\u00f4 m\u1ea5t bao nhi\u00eau ti\u1ec1n? 50 \u0111i\u1ec3m l\u00f4 l\u00e0 bao nhi\u00eau ti\u1ec1n? Ch\u01a1i \u0111i\u1ec3m l\u00f4 c\u00e0ng cao th\u00ec khi tr\u00fang s\u1ebd nh\u1eadn v\u1ec1 s\u1ed1 ti\u1ec1n c\u00e0ng l\u1edbn. D\u01b0\u1edbi \u0111\u00e2y l\u00e0 b\u1ea3ng h\u01b0\u1edbng d\u1eabn c\u00e1ch t\u00ednh \u0111i\u1ec3m l\u00f4 c\u1ee5 th\u1ec3 anh em n\u00ean tham kh\u1ea3o:<\/p>\n1. L\u00f4 l\u00e0 g\u00ec? Khi n\u00e0o \u0111\u01b0\u1ee3c t\u00ednh l\u00e0 tr\u00fang l\u00f4<\/h2>\n
2. \u0110\u00e1nh m\u1ed9t \u0111i\u1ec3m l\u00f4 tr\u00fang bao nhi\u00eau ti\u1ec1n?<\/h2>\n
\u0110\u00e0i mi\u1ec1n B\u1eafc<\/em><\/h3>\n
\u0110\u00e0i Trung<\/em><\/h3>\n
\u0110\u00e0i Nam<\/em><\/h3>\n
3. C\u00e1ch t\u00ednh ti\u1ec1n l\u00f4 xi\u00ean (c\u1ea3 3 mi\u1ec1n)<\/h2>\n
L\u00f4 xi\u00ean 2<\/em><\/h3>\n
L\u00f4 xi\u00ean 3<\/em><\/h3>\n
L\u00f4 xi\u00ean 4<\/em><\/h3>\n
4. C\u00e1ch t\u00ednh \u0111i\u1ec3m l\u00f4 tr\u01b0\u1ee3t<\/h2>\n
\n
5. H\u01b0\u1edbng d\u1eabn c\u00e1ch t\u00ednh \u0111i\u1ec3m l\u00f4 kh\u00e1c c\u1ee5 th\u1ec3<\/h2>\n